benjamin dickman
@benjamindickman.bsky.social
1.4K followers 410 following 2.6K posts
K-12 math educator 🪄♾️ Brookline to Nanjing to NYC Amherst College BA Fulbright Program x2 (🇨🇳+🇵🇭) Teachers College, Columbia University PhD past BU Wheelock (postdoc, Math Edu) cocreated original word game: #FiddleBrix http://tinyurl.com/bmdmaths
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benjamindickman.bsky.social
my favorite #sensemaking excerpt

from:
Kegan, Robert. The evolving self: Problem and process in human development. Harvard University Press, 1982.

preview in google books:
books.google.com/books?id=SP3...

not overtly about 'mathematics' per se but w/e
#iTeachMath ♾️ #MathSky 🧮
screenshot of text beginning "these days my daughter" and ending with "parenthood, friendship, and love"
benjamindickman.bsky.social
yeah I saw some students looking at number theory propositions that were obviously false!

even something like "6n+1 is a multiple of 3" works with the inductive step but not the base case

... food for thought on our next exam or problem set 🤔🤔🤔
Reposted by benjamin dickman
Reposted by benjamin dickman
benjamindickman.bsky.social
here are the inductive steps (abbreviated):

factor:
4^(n+1) + 2 = 4(4^n) + 2 = (3+1)4^n + 2
= 3(4^n) + (4^n + 2)

substitute:
2^(n+3) + 3^(2n+3) = 2(2^(n+2)) + 9(3^(2n+1))
= 2(7m - 3^(2n+1)) + 9(3^(2n+1))
= 7(2m + 3^(2n+1))

multiply:
5^n - 1 = 4m
5^(n+1) - 5 = 20m
5^(n+1) - 1 = 20m+4 = 4(5m+1)
Reposted by benjamin dickman
benjamindickman.bsky.social
For all n ≥ 1, the following propositions are true:

1) 4^n + 2 is div. by 3
2) 2^(n+2) + 3^(2n+1) is div. by 7
3) 5^n - 1 is div. by 4
4) 2^n ≥ n+1

The first three were proved using methods referred to with the verbs: factor, substitute, and multiply; the last was proved by combining inequalities!
benjamindickman.bsky.social
another #DesmosDemo for #iTeachMath & #MathSky!

check out the Emmy-award winning* show from Sara and Sean



*ok it hasn't won anything but it hasn't lost either!
benjamindickman.bsky.social
I saw it. It was great. We were so young 🌱
benjamindickman.bsky.social
here are the inductive steps (abbreviated):

factor:
4^(n+1) + 2 = 4(4^n) + 2 = (3+1)4^n + 2
= 3(4^n) + (4^n + 2)

substitute:
2^(n+3) + 3^(2n+3) = 2(2^(n+2)) + 9(3^(2n+1))
= 2(7m - 3^(2n+1)) + 9(3^(2n+1))
= 7(2m + 3^(2n+1))

multiply:
5^n - 1 = 4m
5^(n+1) - 5 = 20m
5^(n+1) - 1 = 20m+4 = 4(5m+1)
benjamindickman.bsky.social
bonus note if you read this far:

I miswrote the second proposition (I lost a 2!) so ... good luck proving it as posted lol
benjamindickman.bsky.social
For all n ≥ 1, the following propositions are true:

1) 4^n + 2 is div. by 3
2) 2^(n+2) + 3^(2n+1) is div. by 7
3) 5^n - 1 is div. by 4
4) 2^n ≥ n+1

The first three were proved using methods referred to with the verbs: factor, substitute, and multiply; the last was proved by combining inequalities!
benjamindickman.bsky.social
in #MathsToday: four different propositions, each proved by induction.

Fascinatingly, the first three (divisibility statements) were all proved using different but interchangeable methods.

The full statements from the image can be found below 👇🏻
see next post or tweet or whatever for the content of this image
benjamindickman.bsky.social
my headers are cabin, body gentium book basic
benjamindickman.bsky.social
i read Who's Afraid of Gender (previous school year) and it was hard reading in multiple ways (sadly prescient; dense and overly fond of the word phantasm)
benjamindickman.bsky.social
day 2 of LinkedOut games:
still playing them when I first wake up instead of when I'm fully awake; still xcl on phone
benjamindickman.bsky.social
as the good lord intended!!

yes, my initials are a nickname I sometimes use

and, correspondingly re: anagrams,

nickname BD = Ben Dickman

(capitalization held constant!)
benjamindickman.bsky.social
great #2solve pairing today for this Tue solve!
benjamindickman.bsky.social
totally agreed, xcl gotta be on ⌨️ and Zip Tango Queens on 📱

mixed on Sudoku, which isn't my strong suit
benjamindickman.bsky.social
LinkedOut games dropping a public leaderboard [for connections] is going to shift my playing style from wake up [first thing in the morning, still half asleep] to blitz [wait until later, play fully awake]. not sure if this is an improvement!

PS: play #FiddleBrix for true 🔡 joy!!
www.fiddlebrix.com
screenshot of fiddlebrix.com landing page; a 5x5 board contains the letters in play, beneath it are the tiles ("brix") spelling out FiddleBrix; beneath that is the phrase "A colorful daily word puzzle"; at the bottom are two buttons to download (one for Apple and one for Android)
benjamindickman.bsky.social
minimal #2solve for Monday 6 Oct 2025:

01001111 01010110 01000101 01010010 01000110 01001001 01010100 01010011 00100000 01010011 01001000 01000001 01010111 01001100