So
(1/21)/(1/3)=1/7=1/(21/3)
1/3 will go into 8/21 8 times as often as it goes into 1/21
So
(8/21)/(1/3)=8(1/7) = 8(1/(21/3)
4/3 will go into 8/21 4 times fewer than 1/3 will
So
(8/21)/(4/3)=(8/4)(1/7)=(8/4)(1/(21/3))=(8/4)/(21/3)
So
(1/21)/(1/3)=1/7=1/(21/3)
1/3 will go into 8/21 8 times as often as it goes into 1/21
So
(8/21)/(1/3)=8(1/7) = 8(1/(21/3)
4/3 will go into 8/21 4 times fewer than 1/3 will
So
(8/21)/(4/3)=(8/4)(1/7)=(8/4)(1/(21/3))=(8/4)/(21/3)
I’ll wager you get some wrong versions of your surname, too.
People commonly get both my first name and surname wrong; some persist in doing so even after I’ve enlightened them.
I’ll wager you get some wrong versions of your surname, too.
People commonly get both my first name and surname wrong; some persist in doing so even after I’ve enlightened them.
in jig time.
in jig time.
2/3 x 2&1/2 = 1&2/3
since 44 is 2/3 of 66.
2/3 x 2&1/2 = 1&2/3
since 44 is 2/3 of 66.
First instinct: 5 x 1/3 of 66
Next: 66 + 2x 1/3 of 66
Further thought: 2 x 66 - 1/3 of 66.
Further further thought: 3 x 5/3 = 5; 22 x 5
First instinct: 5 x 1/3 of 66
Next: 66 + 2x 1/3 of 66
Further thought: 2 x 66 - 1/3 of 66.
Further further thought: 3 x 5/3 = 5; 22 x 5
I was, in fact, thinking initially of a quantitative (Pythagorean) approach- hence the choice of the 3-4-5 r.a.t.
If understand your argument, the difference in perimeter is
3 - sqrt5?
I was, in fact, thinking initially of a quantitative (Pythagorean) approach- hence the choice of the 3-4-5 r.a.t.
If understand your argument, the difference in perimeter is
3 - sqrt5?
Conceptually hard?
I would say so.
Conceptually hard?
I would say so.