Haha!! Vic was the journalist included on Signal?

I need to emphasize that I have not proven this, but I might spend some time on it after spending some time cleaning the house and cleaning up my gardening areas

Given n decks of p cards, where p is an odd prime and p = 2n-1. You can always deal these cards out into p columns where the previous column has one more than the last, starting with a column with 1 card, and you will be left with no cards when you are done. This also seems to holds for n-1 and p-1