Julia
@foxgrrl.bsky.social
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she/her | Gay Area, CA
∇⋅𝐄=ρ/ε₀
∇⋅𝐁=0
∇⨯𝐄=-∂𝐁/∂t
∇⨯𝐁=μ₀(𝐉 + ε₀(∂𝐄/∂t))
𝐅=q(𝐄 + 𝐯⨯𝐁)
故有之以為利,無之以為用。
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Laelaps
@laelaps.fyi
· 18h
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